about mining success chance

[leloush 7]

 

    // Randomize target mineral to mine

    .@target = rand(getarraysize(.mineral));

     

    // Max range of success

    .@range = .success[.@target * 2 + 1];

     

    // Check if failed

    if(rand(1, .@range) != .success[.@target * 2])

    {

        message strcharinfo(0), "Nothing valuable was excavated...";

        end;

    }

     

    // Get mineral(s)

    getitem .mineral[.@target], .amount[.@target];

    message strcharinfo(0), "You have successfully mined "+ .amount[.@target] +" "+ getitemname(.mineral[.@target]) +"!";

    end;

     

    OnWhisperGlobal:

        // Whisper anything to initialize settings

        message strcharinfo(0), strnpcinfo(1) +" : 'OnInit' label has been intialized.";

         

    OnInit:

        // Minerals

        setarray .mineral[0], 25106, 1011, 984, 985; // Phracon, Emveretarcon, Oridecon, Elunium

        setarray .amount[0],     1,    1,   1,   1; // Amount to mine

setarray .coordinate_x,0,300;

setarray .coordinate_y,0,300;

         

        // Success rate: (x / y)% chance

        setarray .success[0],   1, 5,   // 1/5 (20%)

                                1, 2,   // 1/2 (50%)

                                4, 5,   // 4/5 (80%)

                                1, 50;  // 1/50 (2%)

how to work with the success chance ? this is a part of script from http://herc.ws/board/topic/1886-simple-mining/

 

sry i really can't get on how to work with this format..

 

thanks

[Angelmelody 221]

 

For example :

 

The success chance of item 984 ws setted to  80%, actually the range of  if(rand(1, .@range) != .success[.@target * 2])

 

 was total  5 elements(1~5) ,  the if condition go rand 5 elements  not equal to 1 elements judged to failure change.

 

So the failure change is 4/5 and success chance is 1/5  not  satisfying our setting 80%  success chance

 

Hope you can understand my broken Eng

yes i did.  btw thanks

 

 

but what if i want to add a prize.. where should i put it

 

 

For example :

 

The success chance of item 984 ws setted to  80%, actually the range of  if(rand(1, .@range) != .success[.@target * 2])

 

 was total  5 elements(1~5) ,  the if condition go rand 5 elements  not equal to 1 elements judged to failure change.

 

So the failure change is 4/5 and success chance is 1/5  not  satisfying our setting 80%  success chance

 

Hope you can understand my broken Eng

yes i did.  btw thanks

 

 

but what if i want to add a prize.. where should i put it

 Do you mean add new mining reward ?

 

 

// Minerals

setarray .mineral[0], 1010, 1011, 984, 985, 501; // Phracon, Emveretarcon, Oridecon, Elunium

setarray .amount[0], 5,   3, 1, 1, 1; // Amount to mine

// Success rate: (x / y)% chance

setarray .success[0], 1, 5, // 1/5 (20%)

1, 2, // 1/2 (50%)

4, 5, // 4/5 (80%)

1, 50,  // 1/50 (2%)

  3,  5;  // 3/5 (60%)

Edited December 17, 2013 by Angelmelody

[Triedge 12]

// Success rate: (x / y)% chance	    setarray .success[0],   1, 5,   // 1/5 (20%)							    1, 2,   // 1/2 (50%)							    4, 5,   // 4/5 (80%)							    1, 50;  // 1/50 (2%) 

[leloush 7]

 

// Success rate: (x / y)% chance	    setarray .success[0],   1, 5,   // 1/5 (20%)							    1, 2,   // 1/2 (50%)							    4, 5,   // 4/5 (80%)							    1, 50;  // 1/50 (2%) 

yeah i already knew about this.. but i have hesitation on the format on what item are on the 2% success chance.

[Angelmelody 221]

setarray .mineral[0], 25106, 1011, 984, 985; // Phracon, Emveretarcon, Oridecon, Elunium

 

// Success rate: (x / y)% chance        setarray .success[0],   1, 5,   // 1/5 (20%) -->25106                                1, 2,   // 1/2 (50%) -->1011                                4, 5,   // 4/5 (80%) -->984                                1, 50;  // 1/50 (2%) -->985

 

[leloush 7]

 

setarray .mineral[0], 25106, 1011, 984, 985; // Phracon, Emveretarcon, Oridecon, Elunium

 

// Success rate: (x / y)% chance        setarray .success[0],   1, 5,   // 1/5 (20%) -->25106                                1, 2,   // 1/2 (50%) -->1011                                4, 5,   // 4/5 (80%) -->984                                1, 50;  // 1/50 (2%) -->985

ok thanks .. i think my problem was solve.

[Angelmelody 221]

I don't think the original  formula is correct

 

if(rand(1, .@range) != .success[.@target * 2])

 

should change to

 

if(rand(1, .@range) > .success[.@target * 2])

Edited December 15, 2013 by Angelmelody

[leloush 7]

I don't think the original  formula is correct

 

if(rand(1, .@range) != .success[.@target * 2])

 

should change to

 

if(rand(1, .@range) > .success[.@target * 2])

thank you for your concern..

 

but what are the diff. of this two lines?

Edited December 16, 2013 by leloush

[Angelmelody 221]

For example :

 

The success chance of item 984 was setted to  80%, actually the range of  if(rand(1, .@range) != .success[.@target * 2])  was total  5 elements(1~5) ,  The if condition go rand 5 elements  not equal to 1 element judged to failure change. So the failure change is 4/5 and success chance is 1/5  not  satisfying our setting 80%  success chance .

 

Hope you can understand my broken Eng

Edited December 17, 2013 by Angelmelody

[leloush 7]

For example :

 

The success chance of item 984 ws setted to  80%, actually the range of  if(rand(1, .@range) != .success[.@target * 2])

 

 was total  5 elements(1~5) ,  the if condition go rand 5 elements  not equal to 1 elements judged to failure change.

 

So the failure change is 4/5 and success chance is 1/5  not  satisfying our setting 80%  success chance

 

Hope you can understand my broken Eng

yes i did.  btw thanks

 

 

but what if i want to add a prize.. where should i put it

Edited December 16, 2013 by leloush

[leloush 7]

 

 

For example :

 

The success chance of item 984 ws setted to  80%, actually the range of  if(rand(1, .@range) != .success[.@target * 2])

 

 was total  5 elements(1~5) ,  the if condition go rand 5 elements  not equal to 1 elements judged to failure change.

 

So the failure change is 4/5 and success chance is 1/5  not  satisfying our setting 80%  success chance

 

Hope you can understand my broken Eng

yes i did.  btw thanks

 

 

but what if i want to add a prize.. where should i put it

 

> 

For example :

 

The success chance of item 984 ws setted to  80%, actually the range of  if(rand(1, .@range) != .success[.@target * 2])

 

 was total  5 elements(1~5) ,  the if condition go rand 5 elements  not equal to 1 elements judged to failure change.

 

So the failure change is 4/5 and success chance is 1/5  not  satisfying our setting 80%  success chance

 

Hope you can understand my broken Eng

yes i did.  btw thanks

 

 

but what if i want to add a prize.. where should i put it

 Do you mean add new mining reward ?

 

 

// Minerals

setarray .mineral[0], 1010, 1011, 984, 985, 501; // Phracon, Emveretarcon, Oridecon, Elunium

setarray .amount[0], 5,   3, 1, 1, 1; // Amount to mine

// Success rate: (x / y)% chance

setarray .success[0], 1, 5, // 1/5 (20%)

1, 2, // 1/2 (50%)

4, 5, // 4/5 (80%)

1, 50,  // 1/50 (2%)

  3,  5;  // 3/5 (60%)

 

thank you so much angel. 

 

 

 

but lastly.. if u dont mind.. can u give me an idea of this script.. i want to put an announce to the map after being warped by the npc from outside.

 

example.. ( already in the destination map .. and the npc inside will ( welcome him/her ) )

 

 mellina,63,60,6 script sample 406,{

end;

OnInit:

waitingroom "waiting room",3,strnpcinfo(3)+"::OnStart",2;

end;

OnStart:

warpwaitingpc "guild_vs2",50,50;

announce  "The raid team of "+ rid2name( $@warpwaitingpc[0] ) +" was teleported to the Raid Dungeon!",bc_blue|bc_all;

enablenpc "insidenpc";

end;

}

 

after warped to guild_vs2

 

announce to map (guild_vs2)  welcome this is sample script... etc etc..

thank you in advanced 

[Angelmelody 221]

you can use  mapannounce after warp player to the  mining map

 

mapannounce "guild_vs2", "wellcome ".+rid2name( $@warpwaitingpc[0] )+"....blah blah blah...", 0;

[leloush 7]

you can use  mapannounce after warp player to the  mining map

 

mapannounce "guild_vs2", "wellcome ".+rid2name( $@warpwaitingpc[0] )+"....blah blah blah...", 0;

good am madam.. i just tried to put this here

 

( this is the line inside after the waiting room.. so i think i need to put it here.. but it ddnt work. so im wondering on how to deal with this

after being warped by the waiting room outside. )

 

guild_vs2,34,67,0 script Extreme Raid[Lever] 1907,{

 

    message strcharinfo(0), "Pulling the lever...";

    progressbar "green", .progress2;

specialeffect 234;

set .Spawn,rand(100,100); // How many Monster should spawn?

set .Map$,.Maps$[rand(getarraysize(.Maps$))];

 

 

//------------------

nothing special about the (welcome/introducer)announcer.. but for me it will make sense .. and will make a good story line for this event. that's why i really want to have an announcer before the event start..

Edited December 17, 2013 by leloush